How to plot a solution
In this tutorial we explain the different ways to plot a solution of an optimal control problem.
Let us start by importing the package to define the problem and solve it.
using OptimalControl
using NLPModelsIpopt
Then, we define a simple optimal control problem and solve it.
ocp = @def begin
t ∈ [0, 1], time
x ∈ R², state
u ∈ R, control
x(0) == [-1, 0]
x(1) == [0, 0]
ẋ(t) == [x₂(t), u(t)]
∫( 0.5u(t)^2 ) → min
end
sol = solve(ocp, display=false)
First ways to plot
The simplest way to plot the solution is to use the plot
function with only the solution as argument.
The plot function on a solution of an optimal control problem is an extension of the plot function from the package Plots.jl. Hence, we need to import this package to plot a solution.
using Plots
plot(sol)
As you can see, it produces a grid of subplots. The left column contains the state trajectories, the right column the costate trajectories, and at the bottom we have the control trajectory.
Attributes from Plots.jl can be passed to the plot
function:
- In addition to
sol
you can pass attributes to the full plot, see the attributes plot documentation from Plots.jl for more details. For instance, you can specify the size of the figure. - You can also pass attributes to the subplots, see the attributes subplot documentation from Plots.jl for more details. However, it will affect all the subplots. For instance, you can specify the location of the legend.
- In the same way, you can pass axis attributes to the subplots, see the attributes axis documentation from Plots.jl for more details. It will also affect all the subplots. For instance, you can remove the grid.
- In the same way, you can pass series attributes to the all the subplots, see the attributes series documentation from Plots.jl for more details. It will also affect all the subplots. For instance, you can set the width of the curves with
linewidth
.
plot(sol, size=(700, 450), legend=:bottomright, grid=false, linewidth=2)
To specify series attributes to a specific subplot, you can use the optional keyword arguments state_style
, costate_style
and control_style
which correspond respectively to the state, costate and control trajectories. See the attribute series documentation from Plots.jl for more details. For instance, you can specify the color of the state trajectories and more.
plot(sol;
state_style = (color=:blue,),
costate_style = (color=:black, linestyle=:dash),
control_style = (color=:red, linewidth=2))
From Flow
The previous resolution of the optimal control problem was done with the solve
function. If you use an indirect shooting method and solve shooting equations, you may want to plot the associated solution. To do so, you need to use the Flow
function to reconstruct the solution. See the Indirect Simple Shooting tutorial for an example. In our example, you must provide the maximising control $(x, p) \mapsto p_2$ together with the optimal control problem.
t0 = 0
tf = 1
x0 = [ -1, 0 ]
p0 = costate(sol)(t0)
f = Flow(ocp, (x, p) -> p[2])
sol_flow = f( (t0, tf), x0, p0 )
plot(sol_flow)
You can notice that the time grid has very few points. To have a better visualisation (the accuracy won't change), you can give a finer grid.
sol_flow = f( (t0, tf), x0, p0; saveat=range(t0, tf, 100) )
plot(sol_flow)
Split versus group layout
If you prefer to get a more compact figure, you can use the layout
optional keyword argument with :group
value. It will group the state, costate and control trajectories in one subplot for each.
plot(sol; layout=:group, size=(800, 300))
The default layout value is :split
which corresponds to the grid of subplots presented above.
Additional plots
You can plot the solution of a second optimal control problem on the same figure if it has the same number of states, costates and controls. For instance, consider the same optimal control problem but with a different initial condition.
ocp = @def begin
t ∈ [0, 1], time
x ∈ R², state
u ∈ R, control
x(0) == [-0.5, -0.5]
x(1) == [0, 0]
ẋ(t) == [x₂(t), u(t)]
∫( 0.5u(t)^2 ) → min
end
sol2 = solve(ocp; display=false)
We first plot the solution of the first optimal control problem, then, we plot the solution of the second optimal control problem on the same figure, but with dashed lines.
# first plot
plt = plot(sol; solution_label="(sol1)", size=(700, 500))
# second plot
plot!(plt, sol2; solution_label="(sol2)", linestyle=:dash)
Plot the norm of the control
For some problem, it is interesting to plot the norm of the control. You can do it by using the control
optional keyword argument with :norm
value. The default value is :components
.
plot(sol; control=:norm, size=(800, 300), layout=:group)
Custom plot
You can of course create your own plots by getting the state
, costate
and control
from the optimal control solution. For instance, let us plot the norm of the control for the orbital transfer problem.
using LinearAlgebra
t = time_grid(sol)
x = state(sol)
p = costate(sol)
u = control(sol)
plot(t, norm∘u; label="‖u‖")
- The
norm
function is fromLinearAlgebra.jl
. - The
∘
operator is the composition operator. Hence,norm∘u
is the functiont -> norm(u(t))
.
Normalized time
We consider a LQR example and solve the problem for different values of the final time tf
. Then, we plot the solutions on the same figure considering a normalized time $s=(t-t_0)/(t_f-t_0)$, thanks to the keyword argument time=:normalized
of the plot
function.
# parameters
x0 = [ 0
1 ]
A = [ 0 1
-1 0 ]
B = [ 0
1 ]
# definition
function lqr(tf)
ocp = @def begin
t ∈ [0, tf], time
x ∈ R², state
u ∈ R, control
x(0) == x0
ẋ(t) == A * x(t) + B * u(t)
∫( 0.5(x₁(t)^2 + x₂(t)^2 + u(t)^2) ) → min
end
return ocp
end;
# solve
solutions = []
tfs = [3, 5, 30]
for tf ∈ tfs
solution = solve(lqr(tf); display=false)
push!(solutions, solution)
end
# create plots
plt = plot(solutions[1]; time=:normalized)
for sol ∈ solutions[2:end]
plot!(plt, sol; time=:normalized)
end
# make a custom plot from created plots: only state and control are plotted
N = length(tfs)
px1 = plot(plt[1]; legend=false, xlabel="s", ylabel="x₁")
px2 = plot(plt[2]; label=reshape(["tf = $tf" for tf ∈ tfs], (1, N)), xlabel="s", ylabel="x₂")
pu = plot(plt[5]; legend=false, xlabel="s", ylabel="u")
using Plots.PlotMeasures # for leftmargin, bottommargin
plot(px1, px2, pu; layout=(1, 3), size=(800, 300), leftmargin=5mm, bottommargin=5mm)